Последовательно просматриваем числа a0 , ..., an-1 находим наименьшее i такое, что ai > ai+1 . Поменять ai и ai+1 местами, возобновить просмотр с элемента ai+1 и т.д. Тем самым наибольшее число передвиниться на последнее место. Следующие просмотры начинать опять сначала, уменьшая на единицу количество просматриваемых элементов. Массив будет упорядочен после просмотра, в котором участвовали только первый и второй элементы
Сортировка массива по возрастанию (метод пузырька)
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